CH2==Ch2(g) ----> CH4(g) + C (graphite)
If the decomposition begina at 10 degrees C and 50.0 atm with a gas density of 0.215 g/mL and the temperature increases by 950K, what is the final pressure of the confined gas (ignore the volume of graphite and use the van der waals equation)
3 answers
So what's your problem? Just plug into the van der Waals equation.
I don't know how to throw density into the equation.
scratch that.. i really don't get any of it. formula I have is: (P + (n^2a)/V^2)(V-nb) = nRT
what I can fill in is (P + (n^2(2.25))/V^2)(V-n(.0428)) = n(.0821)(950)
what I can fill in is (P + (n^2(2.25))/V^2)(V-n(.0428)) = n(.0821)(950)
1 answer