95% = mean ± 1.96 SEm
SEm = SD/√n
I'll let you calculate and come to your own conclusions.
Certain data includes 36 body temperatures for which the sample mean is equal to 98.20 °F and standard deviation of 0.62 °F. Using this sample statistics, construct a 95% confidence interval of the mean body temperature. What does the sample suggest about the use of 98.6°F as the mean body temperature?
1 answer