△CDE∼△PQR

. m∠C=13°
, m∠D=65°
. What are the measures of angles P
, Q
, and R

1 answer

Since triangles \( \triangle CDE \) and \( \triangle PQR \) are similar (denoted as \( \triangle CDE \sim \triangle PQR \)), their corresponding angles are equal.

Given:

  • \( m\angle C = 13^\circ \)
  • \( m\angle D = 65^\circ \)

To find the measure of angle \( E \) in triangle \( CDE \): \[ m\angle E = 180^\circ - m\angle C - m\angle D \] \[ m\angle E = 180^\circ - 13^\circ - 65^\circ \] \[ m\angle E = 180^\circ - 78^\circ = 102^\circ \]

Now, since the triangles are similar:

  • \( m\angle P = m\angle C = 13^\circ \)
  • \( m\angle Q = m\angle D = 65^\circ \)
  • \( m\angle R = m\angle E = 102^\circ \)

Therefore, the measures of angles \( P \), \( Q \), and \( R \) are:

  • \( m\angle P = 13^\circ \)
  • \( m\angle Q = 65^\circ \)
  • \( m\angle R = 102^\circ \)