△CDE∼△PQR. m∠C=13°, m∠D=65°. What are the measures of angles P, Q, and R?
3 answers
Since △CDE ∼ △PQR, the corresponding angles are congruent. Therefore, m∠P=13°, m∠Q=65°, and m∠R=180°-13°-65°=102°.
you sure not saying your rong but i am confused
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We are given that △CDE ∼ △PQR. Since these triangles are similar, the corresponding angles are congruent. Furthermore, the ratio of the lengths of corresponding sides in similar triangles is equal.
We know that m∠C = 13° and m∠D = 65°.
Since △CDE ∼ △PQR, we can conclude that m∠P = 13° and m∠Q = 65°, based on the corresponding angles.
To find the measure of angle R, we can use the fact that the angles of a triangle add up to 180°.
m∠R = 180° - m∠P - m∠Q
= 180° - 13° - 65°
= 102°
So, the measures of angles P, Q, and R are m∠P = 13°, m∠Q = 65°, and m∠R = 102°.
We are given that △CDE ∼ △PQR. Since these triangles are similar, the corresponding angles are congruent. Furthermore, the ratio of the lengths of corresponding sides in similar triangles is equal.
We know that m∠C = 13° and m∠D = 65°.
Since △CDE ∼ △PQR, we can conclude that m∠P = 13° and m∠Q = 65°, based on the corresponding angles.
To find the measure of angle R, we can use the fact that the angles of a triangle add up to 180°.
m∠R = 180° - m∠P - m∠Q
= 180° - 13° - 65°
= 102°
So, the measures of angles P, Q, and R are m∠P = 13°, m∠Q = 65°, and m∠R = 102°.
5 answers