Question

Carter wants to use the model above to solve 273÷13. Explain how he would find part a part B and part C of the model.

Answer 1

To solve \(273 \div 13\) using a model, it's common to break down the division process into manageable steps or components, such as parts A, B, and C. While specific models may vary, I can explain a general approach that Carter might take to find each part.

### Part A: Determine How Many Times 13 Fits into 273

1. **Estimate the Quotient**: Start by estimating how many times 13 can fit into 273. It helps to round or find a nearby multiple. For example, since \(13 \times 20 = 260\) and \(13 \times 21 = 273\), we can estimate the quotient to be around 21.

2. **Perform Long Division**: Carter could set up a long division problem.
- Divide \(273\) by \(13\) using long division, starting with the leftmost digits.
- Determine how many times \(13\) fits into \(27\) (the first two digits), which is 2 times (since \(13 \times 2 = 26\)).
- Subtract \(26\) from \(27\), which leaves \(1\). Bring down the next digit, which is \(3\), making it \(13\).

### Part B: Calculate the Remaining Value

3. **Further Division**: With \(13\) (from the previous step) to take care of:
- Now, determine how many times \(13\) fits into \(13\). The answer is 1 (since \(13 \times 1 = 13\)).
- Subtract \(13\) from \(13\) to get 0.

### Part C: Compile the Results

4. **Combine Results**: Combine the results from the division:
- Add up the counts from parts A and B: \(2\) (the first part) + \(1\) (the second part) = \(21\).
- Thus, the complete expression is:
\[
273 \div 13 = 21
\]

In conclusion, Carter would find that \(273 \div 13\) equals \(21\) by systematically breaking down the problem into the manageable parts of estimating, dividing, and compiling results.