To solve 273 ÷ 13 using a model, it's common to break it down into three parts: A, B, and C. Here’s how Carter might approach it:
Part A: Understanding the Division Problem
In Part A, Carter would identify the dividend (273) and the divisor (13). He might write it out in the long division format as follows:
____
13 | 273
In this step, he recognizes that he needs to determine how many times 13 can fit into 273.
Part B: Estimating and Calculating
In Part B, Carter would estimate how many times 13 goes into 273. He could do this by finding a nearby multiple of 13 that is easier to work with.
-
Estimate: What is 13 multiplied by 20?
- 13 × 20 = 260, which is close to 273.
-
Perform the Division:
- Carter can then calculate 273 - 260 to see what remains:
- 273 - 260 = 13.
- He realizes that he can fit 20 groups of 13 into 273, leaving a remainder of 13.
-
Continue Dividing:
- Now he takes the remainder (13) and sees how many times 13 fits into it:
- 13 ÷ 13 = 1.
So, he has 20 from the first part and 1 from this part.
Part C: Combining and Finalizing the Answer
In Part C, Carter would combine the results from parts A and B to conclude:
- From Part A, he found that 20 groups of 13 fit into 273, and from Part B, he found that an additional 1 group fits perfectly into the remainder.
Therefore, combining these, he concludes:
273 ÷ 13 = 20 + 1 = 21.
Finally, Carter can state the complete answer:
- Final Answer: 273 ÷ 13 = 21, with no remainder.
In summary, Carter would break down the division into parts that make it easier to understand and solve the problem step by step.