Question

Carter wants to use the model above to solve 273 / 13 explain how he would find parts A B and C of the model

Answer 1

To solve 273 ÷ 13 using a model, it's common to break it down into three parts: A, B, and C. Here’s how Carter might approach it:

### Part A: Understanding the Division Problem
In Part A, Carter would identify the dividend (273) and the divisor (13). He might write it out in the long division format as follows:

```
____
13 | 273
```

In this step, he recognizes that he needs to determine how many times 13 can fit into 273.

### Part B: Estimating and Calculating
In Part B, Carter would estimate how many times 13 goes into 273. He could do this by finding a nearby multiple of 13 that is easier to work with.

1. **Estimate**: What is 13 multiplied by 20?
- 13 × 20 = 260, which is close to 273.

2. **Perform the Division**:
- Carter can then calculate 273 - 260 to see what remains:
- 273 - 260 = 13.
- He realizes that he can fit 20 groups of 13 into 273, leaving a remainder of 13.

3. **Continue Dividing**:
- Now he takes the remainder (13) and sees how many times 13 fits into it:
- 13 ÷ 13 = 1.

So, he has 20 from the first part and 1 from this part.

### Part C: Combining and Finalizing the Answer
In Part C, Carter would combine the results from parts A and B to conclude:

- From Part A, he found that 20 groups of 13 fit into 273, and from Part B, he found that an additional 1 group fits perfectly into the remainder.

Therefore, combining these, he concludes:

273 ÷ 13 = 20 + 1 = 21.

Finally, Carter can state the complete answer:

- **Final Answer**: 273 ÷ 13 = 21, with no remainder.

In summary, Carter would break down the division into parts that make it easier to understand and solve the problem step by step.