v^2 = rg tan(θ)
2v dv/dt = rg sec^2(θ) dθ/dt
Cars on a certain roadway travel on a circular arc of radius r. In order not to rely on friction alone to over come the centrifugal force, the road is banked at an angle of magnitude 0 from the horizontal. The banking angle must satisfy the equation
rg tan 0 = v^2
where v is the velocity of the cars and g = 32 ft/sec^2 is the acceleration due to gravity. Find the relationship between the related rates dv/dt and d0/dt.
= v2
0 is angle I'm not sure how to input the angle symbol
1 answer