Carlos is playing basketball this season. He is trying to average 25 points per game. He has scored 27, 18, 24, 32, 15, and 27 points in the previous 6 games. What equation can help you find the score for the last game that will give Carlos an average of 25 points?(1 point)

Question

Responses

27+18+24+32+15+17+s7=25
Start Fraction 27 plus 18 plus 24 plus 32 plus 15 plus 17 plus s over 7 End Fraction equals 25

143s7=25
Start Fraction 143 s over 7 End Fraction equals 25

27+18+24+32+15+277+s=25
Start Fraction 27 plus 18 plus 24 plus 32 plus 15 plus 27 over 7 End Fraction plus s equals 25

27+18+24+32+15+27+s7=25

Answer 1

To find the score for the last game that will give Carlos an average of 25 points per game over 7 games, we need to set up an equation based on the average formula:

The average is calculated as the total score divided by the number of games. If we let \( s \) represent the score of the last game, the equation can be set up as follows:

1. First, calculate the total points scored in the first 6 games: \( 27 + 18 + 24 + 32 + 15 + 27 = 143 \).

2. To find the average after 7 games, the equation will be: \[ \frac{143 + s}{7} = 25 \]

3. From this, we can deduce that the correct equation is: \[ 143 + s = 25 \times 7 \] or in simplified terms: \[ 143 + s = 175 \]

Therefore, the equation that will help you find the score for the last game is: \[ \frac{143 + s}{7} = 25 \]

The most suitable choice from the provided responses is: 27 + 18 + 24 + 32 + 15 + 27 + s / 7 = 25

Answer 2

The adventure club is selling candy bars to go on their annual outing. The bars sell for $2 a bar. The club bought 725 bars for $400. The club needs to make at least $1,000 to go on their trip. Which inequality best represents this problem, and are the 725 bars a viable option to make enough profit?(1 point)
Responses

2b−400≥1000 , and no, it is not a viable option.
2 b minus 400 greater than or equal to 1000 , and no, it is not a viable option.

2b−400≤1000 , and yes, it is a viable option.
2 b minus 400 less than or equal to 1000 , and yes, it is a viable option.

2b−400≤1000 , and no, it is not a viable option.
2 b minus 400 less than or equal to 1000 , and no, it is not a viable option.

2b−400≥1000 , and yes, it is a viable option.

Answer 3

First, let's break down the problem to create the correct inequality.

1. Revenue from selling candy bars: The candy bars are sold for $2 each. If \( b \) is the number of bars sold, the revenue can be represented as \( 2b \).

2. Cost of candy bars: The club bought 725 bars for $400. The profit made from selling \( b \) bars can be expressed as: \[ \text{Profit} = \text{Revenue} - \text{Cost} = 2b - 400 \]

3. Profit requirement: The club needs to make at least $1,000 profit. Therefore, we need the inequality: \[ 2b - 400 \geq 1000 \]

Now, let's rearrange this inequality to find out how many bars need to be sold:

\[ 2b - 400 \geq 1000 \] Add 400 to both sides: \[ 2b \geq 1400 \] Now, divide by 2: \[ b \geq 700 \]

Since they bought 725 bars, selling at least 700 bars is indeed viable, as they have more than enough bars to sell.

Thus, the correct option is: 2b − 400 ≥ 1000, and yes, it is a viable option.

Answer 4

A horse trainer has a bag of pink sugar mints for horse treats. She needs five treats per training session. The bag holds 42 mints. Which equation shows the number of horses that she can train and is a solution a viable option?(1 point)
Responses

h−5=42 and h=47, which is not viable.
h minus 5 equals 42 and h equals 47 , which is not viable.

5h=42, so h=8.4 horses, which is viable.
5 h equals 42 , so h equals 8.4 horses, which is viable.

5h=42, so h=8.4 horses, which is not viable.
5 h equals 42 , so h equals 8.4 horses, which is not viable.

h5=42 and h=210, which is not viable.

Answer 5

To determine how many horses the trainer can train based on the number of treats available, we can set up an equation based on the given information.

1. Treats per training session: The trainer needs 5 treats for each horse per training session.
2. Total number of mints available: The bag holds 42 mints.

Let \( h \) be the number of horses that can be trained. The equation that represents the situation will be:

\[ 5h = 42 \]

Now we can solve for \( h \):

\[ h = \frac{42}{5} = 8.4 \]

This means the trainer can train 8.4 horses, which implies she can train at most 8 horses in full sessions.

Next, let's evaluate the options given:

1. h − 5 = 42 and h = 47, which is not viable: Incorrect, because it does not represent the situation.
2. 5h = 42, so h = 8.4 horses, which is viable: This is incorrect because while the math is correct, 8.4 is not a viable number of horses.
3. 5h = 42, so h = 8.4 horses, which is not viable: This one is correct because you cannot train a fractional part of a horse in complete sessions.
4. h5 = 42 and h = 210, which is not viable: Incorrect, because it does not represent the situation properly.

Thus, the correct response is: 5h = 42, so h = 8.4 horses, which is not viable.