dHrxn = (n*dHf products) - (n*dHf reactants)
dHrxn = (2*dHf CO2) - (2*dHf CO)
-566 = 2*-393.5)-(2x)
Solve for x. I picked up the = -393.5 kJ/mol from tables in my text.
Carbon monoxide reacts with oxygen to form carbon dioxide by the following reaction:
2CO2 + O2 yields 2CO2
Delta H for this reaction is -566 kJ/mol run. What is the delta H for CO?
1). +270 kJ/mol
2). -110 kJ/mol
3). +65 kJ/mol
4). -405 kJ/mol
5). -65 kJ/mol
6). -182 kJ/mol
7). +135 kJ/mol
2 answers
there's no right ansswer