Cara tracked the population of fish in a pond. At the end of the first year, she counted 8 fish. Over the years, the population tripled each year.
Which equation can be used to determine the number of fish, f, after t years?
f = 3 ⋅ 8^(t-1)
f = 8 ⋅ 3^t
f = 3 ⋅ 8^t
f = 8 ⋅ 3^(t-1)
i think it may be f = 8 ⋅ 3^t ? not sure
4 answers
or maybe it's f = 3 ⋅ 8^t ??
triples every year, so you multiply by powers of 3, not 8.
And since t=0 is the first year, after t years, it is 8*3^t
so pick B
And since t=0 is the first year, after t years, it is 8*3^t
so pick B
says it's wrong
rubbish. For t=0, no years have passed, and you have the starting population of 8 fish.
After 1 year has passed, the population has tripled once, to 8*3 = 8*3^1
Note that the nth term of the GP is 8*3^(t-1) but that does not apply here.
After 1 year has passed, the population has tripled once, to 8*3 = 8*3^1
Note that the nth term of the GP is 8*3^(t-1) but that does not apply here.