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Car moving down road accelerates at uniform rate 2.8 m/s/s for 4.63 s to reach a speed of 106.7 m/s.

1) How fast was the car initially moving?
2) What distance did it travel during the a/c/c.?

1 answer

This is straightforward stuff...

vf= vi + a*t solve for vi
d= vi*t + 1/2 a t^2

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