Car A, with mass of 1735kg, was traveling north at 45.5km/h and car B, with a mass of 2540kg, was traveling west at 37.7km/h when they collided at an intersection. if the cars stuck together after the collision, what was their combined momentum? Was the collision elastic or inelastic?
3 answers
It is NOT an elastic collision, they stuck together. Combined momentum= sum of initial momentums. Do this as vector addition.
Since the directions are north and west you directly use the Pythagoras theorem to find the resultant speed?? and the tan of the two two get the angle??
Given:
Mass of Car a (Ma)= 1735kg, Vai= 45.5 km/hour= 12.64m/s
Mass of Car b (Mb) = 2540kg, Vbi= 37.7km/hour= 10.47m/s
pi = pf
MaVai+ MbVbi = Vf (m1+m2)
(175)(12.64) + (2540)(10.47) = pf
pf = 28805.8 J
Elastic collision because Pi=Pf
Mass of Car a (Ma)= 1735kg, Vai= 45.5 km/hour= 12.64m/s
Mass of Car b (Mb) = 2540kg, Vbi= 37.7km/hour= 10.47m/s
pi = pf
MaVai+ MbVbi = Vf (m1+m2)
(175)(12.64) + (2540)(10.47) = pf
pf = 28805.8 J
Elastic collision because Pi=Pf
2 answers