Coefficient of friction is:
u=v^2/(r*g)
now lets apply this formula to the problem
Set Car A = Car B
and you get
V_a^2/V_b^2 = u_a/u_b
v_b=v_a*sqrt(u_b/u_a)
(13.8)*sqrt(.843/.333) = 21.95 m/s
Car A uses tires for which the coefficient of static friction is 0.333 on a particular unbanked curve. The maximum speed at which the car can negotiate this curve is 13.8 m/s. Car B uses tires for which the coefficient of static friction is 0.843 on the same curve. What is the maximum speed at which car B can negotiate the curve?
3 answers
Note that "r" and "g" cancels out when you put the coefficient of friction equal to each other for car A and car B
Thank you Don. A great way of clarifying through the steps, very detail oriented. Thanks again!
1 answer