To find the shortest distance between Car A and Car B, we can treat them as vectors and find the magnitude of the vector that connects their positions.
Let's denote the position of Car A as (0, 0) and position of Car B as (8, 0).
The velocity vector for Car A is (80, 0) and the velocity vector for Car B is (0, -50).
To find the direction vector connecting Car A to Car B, we subtract the position vector of Car A from the position vector of Car B:
Direction vector = (8, 0) - (0, 0) = (8, 0)
The magnitude of the direction vector can be calculated as:
Magnitude = sqrt((8)^2 + (0)^2) = sqrt(64) = 8
Therefore, the shortest distance between Car A and Car B is 8 km.
Car A is moving due east at 80 km/h. Car B, 8 km to the east, is moving due south at 50 km/h. Calculate the shortest distance between A and B.
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