at time t seconds after passing car B,
car A has gone 10t
car B has gone 1/2 a(t-10)^2 = .25(t-10)^2
the two distances are equal at time t=58.28
so, both have gone 582.8m
Car A is moving at a constant speed of 10.0 m/s and passes Car B which is at rest. 10 seconds after, the latter follows with an acceleration of 0.5 m/s2. Determine the distance that the latter has to travel before it overtakes the former.
does it require quadratic formula? Oh please help please. can you please explain and give me the formulas needed?
1 answer
1 answer