Car A is moving at a constant speed of 10.0 m/s and passes Car B which is at rest. 10 seconds after, the latter follows with an acceleration of 0.5 m/s2. Determine the distance that the latter has to travel before it overtakes the former.

does it require quadratic formula? Oh please help please. can you please explain and give me the formulas needed?

1 answer

at time t seconds after passing car B,

car A has gone 10t
car B has gone 1/2 a(t-10)^2 = .25(t-10)^2

the two distances are equal at time t=58.28

so, both have gone 582.8m
Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
  1. So, please check my answers here:1. Which example identifies a change in motion that produces acceleration? A) A speed skater
    1. answers icon 2 answers
  2. If an object is moving at a constant acceleration then it could NOT be....A. changing its direction B. moving in a straight line
    1. answers icon 2 answers
more similar questions