Capture both of the lines by entering ordered pairs for points on these lines: y=2x+7 y=3x-3

Answer 1

To capture points on the line y = 2x + 7, we can choose any value for x and substitute it into the equation to find the corresponding y-value. Let's use x = 0, 1, and 2:

For x = 0:
y = 2(0) + 7
y = 0 + 7
y = 7

So the first point on the line y = 2x + 7 is (0, 7).

For x = 1:
y = 2(1) + 7
y = 2 + 7
y = 9

The second point on the line y = 2x + 7 is (1, 9).

For x = 2:
y = 2(2) + 7
y = 4 + 7
y = 11

The third point on the line y = 2x + 7 is (2, 11).

Now let's find points on the line y = 3x - 3:

For x = 0:
y = 3(0) - 3
y = 0 - 3
y = -3

The first point on the line y = 3x - 3 is (0, -3).

For x = 1:
y = 3(1) - 3
y = 3 - 3
y = 0

The second point on the line y = 3x - 3 is (1, 0).

For x = 2:
y = 3(2) - 3
y = 6 - 3
y = 3

The third point on the line y = 3x - 3 is (2, 3).

In summary, the ordered pairs for points on the line y = 2x + 7 are (0, 7), (1, 9), and (2, 11). The ordered pairs for points on the line y = 3x - 3 are (0, -3), (1, 0), and (2, 3).