I see no way to do this. All you know is the area. There are many isosceles trapezoids that can have such an area, each with a different perimeter.
For instance, if the height is 5, then (a+b)/2 = 29
and the slant sides are of length
s^2 = 5^2 + ((b-a)/2)^2
So, the perimeter can have many possible values. And that's just using h=5.
Something more needs to be nailed down.
Can't figure this out... :(
An isosceles trapezium with its longest side facing upward has an area of 145cm^2. Find the amount of material needed to make up the sides of the trapezium, when the side facing upward does not need to be covered (i.e. Perimeter - length of longest side).
I assume you'd sub 145 as the area into the trapezium area rule a= h((a+b)/2)
Or perhaps divide it into a rectangle and 2 triangles?? Any help appreciated!
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