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Cand D are two observation posts on the same horizontal ground at the foot A of a vertical tower AB.the tower is 18m due north...Asked by dayo
Cand D are two observation posts on the same horizontal ground at the foot A of a vertical tower AB.the tower is 18m due north of D and 24m east of C.the angle of elevation of B from D is 35¡ã.calculate to three s.f the height AB,distance CD,angle of elevation from C,bearing...
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Answered by
MathMate
As with all geometry problems, draw a diagram (plan).
You will find that in right triangle ABD, we know
AD=18 m
∠ADB=35°
Solve this triangle to get
mAB=AD tan(ADB)
=18tan(35°)
For right triangle CAB,
mAB (known from above)
mCA = 24m
=>
∠ACB=tan<sup>-1</sup>(mAB/mCA)
=angle of elevation of B relative to C.
Distance CD can be found by Pythagoras theorem.
You will find that in right triangle ABD, we know
AD=18 m
∠ADB=35°
Solve this triangle to get
mAB=AD tan(ADB)
=18tan(35°)
For right triangle CAB,
mAB (known from above)
mCA = 24m
=>
∠ACB=tan<sup>-1</sup>(mAB/mCA)
=angle of elevation of B relative to C.
Distance CD can be found by Pythagoras theorem.
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