3x+4y=34
3x+2y=26
(1)3X+4Y=34
(-1)3X+2Y=26
3X+4Y=34
-3X+(-2Y)=-26
6Y=60
Y=10
3X+2(10)=26
3X+20=26
3X=26-20
3X=6
X=2
can you solve this set of equations using the elimination method?
3x+4y=34 and 3x+2y=26
2 answers
???
4y-2y=34-26
4y-2y=34-26