To solve this problem, we can use a system of equations. Let's denote:
- \( c \) = number of chickens
- \( r \) = number of rabbits
We know the following:
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Each chicken and rabbit has one head, and there are a total of 35 heads. This gives us our first equation: \[ c + r = 35 \]
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Chickens have 2 feet, and rabbits have 4 feet. The total number of feet is 94, which gives us our second equation: \[ 2c + 4r = 94 \]
Now we can solve this system of equations.
First, we simplify the second equation. We can divide the entire equation by 2: \[ c + 2r = 47 \]
Now, we have the following system of equations:
- \( c + r = 35 \)
- \( c + 2r = 47 \)
Next, we can subtract the first equation from the second: \[ (c + 2r) - (c + r) = 47 - 35 \] This simplifies to: \[ r = 12 \]
Now that we know there are 12 rabbits, we can substitute \( r \) back into the first equation to find \( c \): \[ c + 12 = 35 \] \[ c = 35 - 12 = 23 \]
Therefore, the solution to the problem is:
- Number of chickens = 23
- Number of rabbits = 12
In conclusion:
- There are 23 chickens and 12 rabbits.