Ask a New Question

can you solve the quadratic function?

y = 2x^2 + 3

1 answer

2 x ^ 2 + 3 = 0 Subtract 3 to both sides

2 x ^ 2 + 3 - 3 = 0 - 3

2 x ^ 2 = - 3 Divide both sides by 2

x ^ 2 = - 3 / 2 Take square root of both sides

x = + OR - square root ( - 3 / 2 )

x = + OR -

i * square root ( - 3 / 2 )

Ask a New Question or answer this question.

Similar Questions

To determine the zeros of the quadratic function \( y = 2x^2 + 9x + 4 \), we will set the equation equal to zero and solve for
1. 1 answer
Given the quadratic function f (a) = d^2 - 7d + 6Factor the equation into a binomial product. Solve for the roots of the
1. 1 answer
Given the quadratic function f (a) = d^2 - 7d + 6Factor the equation into a binomial product. Solve for the roots of the
1. 2 answers
1. How do we determine te quadratic function given its table of values?2. How can we use the general form or standard form of
1. 1 answer

more similar questions