OH NO, you cannot add unlike terms
x^2 - 8x + 16
=(x-4)(x-4)
check it by expanding
BTW, you did not have an "equation".
did you have x^2 - 8x + 16 = 0 ?
then (x-4)(x-4)=0
x = -4
can you please help me solve this quadadratic equasionby factoring :
x^2-8x+16 would this be the right way
8x^3+16 to start
3 answers
The factors of x^2 - 8x + 16 are (x-4)(x-4)
You did not write an equation.
If you had written x^2 -8x + 16 = 0, which IS an equation, the answer would be x = 4. That would be the only answer, since both factors are zero when x = 4.
You did not write an equation.
If you had written x^2 -8x + 16 = 0, which IS an equation, the answer would be x = 4. That would be the only answer, since both factors are zero when x = 4.
I obviously meant x = 4 (not -4)
(that "oldtimers" syndrome hitting again)
(that "oldtimers" syndrome hitting again)
1 answer