surely you can find the y-intercept!! Just set x=0
As for x- intercepts, note that
y = x^2 √(3-x) √(3+x)
now where does
x^2 √(3-x) √(3+x) = 0
??
Can you please help me find the x and y intercepts of this equation. How do I solve this?
y= x^2 √9-x^2
1 answer