Asked by Gina
Can you please go step by step, Ill show what I did and you can correct me.
The question is:
a+a(x+1)
My way:
a+a(x+1)
2a(x+1)
2ax+2a
Could someone please check over this and provide a correct answer and my error.
Thanks in advance.
a+a(x+1) does not equal 2a(x+1)
If it was (a+a)(x+1), then that would work, but it's not.
The correct next step is:
a+a(x+1)=a+ax+a
Thank-you
You may not add the terms a and a(x+1) since they are not the same. You can add a and a or a(x+1) and a(x+1) but not the in-between.
Firt, expand the second term by multiplying each term withing the parentheses by a.
a+a(x+1)=
a + ax + a =
then you may add the same terms to obtain:
2a + ax =
I don't know where you are going with this equation or the final form in which it is to be found; however, you can now factor out a to obtain
a(2+x). That is how I would leave it.
The question is:
a+a(x+1)
My way:
a+a(x+1)
2a(x+1)
2ax+2a
Could someone please check over this and provide a correct answer and my error.
Thanks in advance.
a+a(x+1) does not equal 2a(x+1)
If it was (a+a)(x+1), then that would work, but it's not.
The correct next step is:
a+a(x+1)=a+ax+a
Thank-you
You may not add the terms a and a(x+1) since they are not the same. You can add a and a or a(x+1) and a(x+1) but not the in-between.
Firt, expand the second term by multiplying each term withing the parentheses by a.
a+a(x+1)=
a + ax + a =
then you may add the same terms to obtain:
2a + ax =
I don't know where you are going with this equation or the final form in which it is to be found; however, you can now factor out a to obtain
a(2+x). That is how I would leave it.
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