can you pleaaaaase help me find the area between y=cos(4x) and y=1-cos(4x) 0<=x<=pi/4
i tried to solve it, and i got like : 2*sqrt3+ pi/12
is it right? if not please tell me how can i solve it...i'm really confused
2 answers
Graph it first. See where the curves meet. If they meet at some angle less than PI/4, then you will have to break up the integration (upper-lower)dx into segments 1->meeting point> otherwise you get a "negative" area which will subtract from your area.
i did all that, i found Pi/12
then , i took the integral from 0 to pi/12, and from pi/12 to pi/4
and i got:
integr from 0 to pi/12 cos(4x)-(1-cos(4x) + integ from pi/12 to pi/4 1-cos(4x)-cos(4x)
but i'm not sure if it was right or not...can u check with me please?
then , i took the integral from 0 to pi/12, and from pi/12 to pi/4
and i got:
integr from 0 to pi/12 cos(4x)-(1-cos(4x) + integ from pi/12 to pi/4 1-cos(4x)-cos(4x)
but i'm not sure if it was right or not...can u check with me please?
0 answers