can you help me with this

Question

Calculate the value of

OH from the given

Note: The ion product of water = 1.0 x 10~14

Part 1 of 2

H3 0+ | in each solution and label the solution as acidic, basic, or neutral.

M

(Choose one)

Be sure your answer has the correct number of significant figures.

H30+=10^-5 M

[он]=

This solution is

Part 2 [H30+]=3.8 x 10-7 M
OH^-=

what is the answer for part 1 and 2

Answer 1

Part 1:

[H3O+] = 10^-5 M

To find [OH-], we can use the ion product of water:

[H3O+][OH-] = 1.0 x 10^-14

10^-5 [OH-] = 1.0 x 10^-14

[OH-] = 1.0 x 10^-14 / 10^-5

[OH-] = 1.0 x 10^-9 M

Since [OH-] > 1.0 x 10^-7 M, this solution is basic.

Answer for Part 1: [OH-] = 1.0 x 10^-9 M, solution is basic.

Part 2:

[H3O+] = 3.8 x 10^-7 M

Using the ion product of water:

[H3O+][OH-] = 1.0 x 10^-14

3.8 x 10^-7 [OH-] = 1.0 x 10^-14

[OH-] = 1.0 x 10^-14 / 3.8 x 10^-7

[OH-] ≈ 2.63 x 10^-8 M

Since [OH-] < 1.0 x 10^-7 M, this solution is acidic.

Answer for Part 2: [OH-] ≈ 2.63 x 10^-8 M, solution is acidic.

I hope this helps! Let me know if you have any further questions.