Part 1:
[H3O+] = 10^-5 M
To determine if the solution is acidic, basic, or neutral, we need to compare the concentration of H3O+ ions to the ion product of water (1.0 x 10^-14).
Since [H3O+] is less than the ion product of water, the solution is neutral.
Part 2:
[H3O+] = 3.8 x 10^-7 M
To calculate the value of OH-, we can use the equation for the ion product of water:
[H3O+][OH-] = 1.0 x 10^-14
We can rearrange the equation to solve for [OH-]:
[OH-] = (1.0 x 10^-14) / [H3O+]
[OH-] = (1.0 x 10^-14) / (3.8 x 10^-7)
[OH-] = 2.63 x 10^-8 M
So the value of OH- is 2.63 x 10^-8 M.
can you help me with this
Calculate the value of
OH from the given
Note: The ion product of water = 1.0 x 10~14
Part 1 of 2
H3 0+ | in each solution and label the solution as acidic, basic, or neutral.
M
(Choose one)
Be sure your answer has the correct number of significant figures.
H30+=10^-5 M
[он]=
This solution is
Part 2 [H30+]=3.8 x 10-7 M
OH^-=
1 answer