To calculate the value of [OH-], we can use the relationship between [H3O+] and [OH-] in water:
[H3O+] * [OH-] = 1.0 x 10^-14
Given that [H3O+] = 2.6 x 10^-12 M, we can plug this value into the equation to solve for [OH-]:
(2.6 x 10^-12) * [OH-] = 1.0 x 10^-14
[OH-] = 1.0 x 10^-14 / 2.6 x 10^-12
[OH-] = 3.85 x 10^-3 M
So, [OH-] = 3.85 x 10^-3 M
Since [OH-] is greater than 1.0 x 10^-7 M, the solution is considered basic.
can you help me with this Calculate the value of [OH" ] from the given | H3O+ | in each solution and label the solution as acidic, basic, or neutral. Be sure each of your answer entries has
the correct number of significant figures.
Note: Reference the Fundamental constants table for additional information.
Part 1 of 2
H30+=2.6x10-12 M
[OH-]=
This solution is
what is the calculation
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H30+=9.8x1071
OH=
This solution is
M
(Choose one)
1 answer
1 answer