To calculate the value of [OH-], we can use the equation Kw = [H3O+][OH-]. Given that [H3O+] = 2.6x10^-12 M, we can rearrange the equation to solve for [OH-]:
Kw = [H3O+][OH-]
1.0x10^-14 = (2.6x10^-12)[OH-]
[OH-] = 1.0x10^-14 / 2.6x10^-12
[OH-] = 3.85x10^-3 M
Since the value of [OH-] is greater than 1.0x10^-7 M, the solution is considered basic.
can you help me with this Calculate the value of [OH" ] from the given | H3O+ | in each solution and label the solution as acidic, basic, or neutral. Be sure each of your answer entries has
the correct number of significant figures.
Note: Reference the Fundamental constants table for additional information.
Part 1 of 2
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