1. For [H3O+] = 10^-5 M, the value of [OH-] can be calculated using the equation [H3O+][OH-] = 1.0 x 10^-14.
[OH-] = 1.0 x 10^-14 / 10^-5
[OH-] = 1.0 x 10^-9 M
The correct number of significant figures is 2. The standard form is 1.0 x 10^-9 M.
2. For H3O+ = 5.7 x 10^-8, the value of [OH-] can be calculated using the equation [H3O+][OH-] = 1.0 x 10^-14.
[OH-] = 1.0 x 10^-14 / 5.7 x 10^-8
[OH-] = 1.754 x 10^-7 M
The correct number of significant figures is 4. The standard form is 1.754 x 10^-7 M.
The solutions can be labeled as acidic, basic, or neutral based on the value of [OH-]. If [OH-] > 1 x 10^-7 M, the solution is basic. If [OH-] < 1 x 10^-7 M, the solution is acidic. If [OH-] = 1 x 10^-7 M, the solution is neutral.
can you help me mwith this write the correct significant figure and standard form
Calculate the value of OH from the given H3O+ in each solution and label the solution as acidic, basic, or neutral.
Note: The ion product of water = 1.0 x 10~14
Part 1 of 2
Be sure your answer has the correct number of significant figures.
[H30+]=10-5 M
[OH7]=
This solution is (Choose one)
Calculate the value of OH from the given H3O+ in each solution and label the solution as acidic, basic, or neutral.
Note: The ion product of water = 1.0 x 10~14
Part 2 of 2
Be sure your answer has the correct number of significant figures.
H3O+ =5.7×10-8
[OH ]=
1 answer