can you help me get started on this integral by parts?
4
S sqrt(t) ln(t) dt
1
please help! thanks!
Integral t^(1/2)Ln(t)dt =
2/3 t^(3/2)Ln(t)-
2/3 Integral t^(1/2) dt =
2/3 t^(3/2)Ln(t) - 4/9 t^(3/2)
Simpler method:
Integral t^(a)dt = t^(a+1)/(a+1)
Integral d/da [t^(a)]dt =
d/da [t^(a+1)/(a+1)] ----->
Integral t^(a)Ln(t)dt =
t^(a+1)Ln(t)/(a+1) - t^(a+1)/(a+1)^2
Finally put a = 1/2.