Asked by Lola
Can you help me find the derivative of these problems...Every time I try doing these I don't get the right answer.
All of these are fractions;
(x)/(2+x)=
(x^2+3)/(x^3-2)=
(2π)/(x^2-x)=
These are not fractions;
(3x^3/2 tanx)=
(3x^1/2 sinx)=
(4secx tanx)=
(x^2 cotx)=
(x^1/2 cscxsinx)=
Please help me, on my homework it already has the answers to check my results but for some reason I keep ending up with the wrong answer.
All of these are fractions;
(x)/(2+x)=
(x^2+3)/(x^3-2)=
(2π)/(x^2-x)=
These are not fractions;
(3x^3/2 tanx)=
(3x^1/2 sinx)=
(4secx tanx)=
(x^2 cotx)=
(x^1/2 cscxsinx)=
Please help me, on my homework it already has the answers to check my results but for some reason I keep ending up with the wrong answer.
Answers
Answered by
Damon
(2+x) d/dx (x) + x d/dx (2+x)
(2 + x) + x(1)
2 + 2 x
2(x+1)
(2 + x) + x(1)
2 + 2 x
2(x+1)
Answered by
Lola
..I'm not sure I understand
Answered by
Damon
mistook / for times
(bottom*derivative of top - top * derivative of bottom)/bottom^2
(x)/(2+x)=
= [(x+2)(1)-x(1) /(x+2)^2
= [ x+2 -x ] /(x+2)2
= 2/(x+2)^2
(bottom*derivative of top - top * derivative of bottom)/bottom^2
(x)/(2+x)=
= [(x+2)(1)-x(1) /(x+2)^2
= [ x+2 -x ] /(x+2)2
= 2/(x+2)^2
Answered by
Lola
Oh okayyyyyyyy, I see it now, thanks
Answered by
Lola
Could you perhaps do one of the ones on the bottom that are not in fraction form, cause I have a hard time doing the ones that have cos,sin,sec, and tan in them.
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