To determine the possible genotypes and phenotypes of the children from a man who is Tt (heterozygous for tongue-curling) and a woman who is also Tt, we can use a Punnett square.
The genotypes of the parents:
- Father: Tt
- Mother: Tt
Using a Punnett square for the Tt x Tt cross:
T | t
------------------
T | TT | Tt
------------------
t | Tt | tt
From this Punnett square, we can see the possible genotypes for their children:
- TT - Homozygous dominant
- Tt - Heterozygous
- tt - Homozygous recessive
Now, let's summarize the phenotypes and the percent chance for each genotype:
- TT: Phenotype (curl): 1 way to have TT
- Tt: Phenotype (curl): 2 ways to have Tt (Tt or tT)
- tt: Phenotype (no curl): 1 way to have tt
Now calculating the probabilities:
- TT: 1 out of 4 = 25%
- Tt: 2 out of 4 = 50%
- tt: 1 out of 4 = 25%
So, the completed table would be:
| Genotype | Phenotype (curl or no curl) | Percent Chance | |----------|---------------------------|----------------| | TT | curl | 25 | | Tt | curl | 50 | | tt | no curl | 25 |
Thus, filling in the blanks:
Blank 1: TT
Blank 2: curl
Blank 3: 25
Blank 4: Tt
Blank 5: curl
Blank 6: 50
Blank 7: tt
Blank 8: no curl
Blank 9: 25