can you correct the rest for me please?

Express each as a function of theta:

a. sin (270deg + theta)= cos theta
b. cos (pi + theta)= -cos theta
c. tan (810 + theta)= ?????
d. sin (theta - 180)= -sin theta

1 answer

a) I get -cos theta

b) -cos theta yes

c) 810 = 360*2 + 90
so really tan (90+theta) =-cotan (theta)

d) -sin theta is correct
Similar Questions
  1. can you correct the rest for me please?Express each as a function of theta: a. sin (270deg + theta)= cos theta b. cos (pi +
    1. answers icon 0 answers
  2. can you correct the rest for me please?Express each as a function of theta: a. sin (270deg + theta)= cos theta b. cos (pi +
    1. answers icon 0 answers
    1. answers icon 2 answers
  3. a) Express f(theta) = 4cos theta - 6sin theta in the form r cos(theta + alpha)b) Hence find the general solution of the equation
    1. answers icon 3 answers
more similar questions