Asked by Alexis
Can you check the following questions,please?
Simplify
30. (-2y)^0/(3x^2)^-3
= 1/(3^-3)(x^-6)
= 1/-27x^-6
= 27x^6
42. (-7x^5/14y^3)^3
= (-1^3)(x^15)/(2^3)(y^9)
= (-1x^15)/8y^9
Simplify
30. (-2y)^0/(3x^2)^-3
= 1/(3^-3)(x^-6)
= 1/-27x^-6
= 27x^6
42. (-7x^5/14y^3)^3
= (-1^3)(x^15)/(2^3)(y^9)
= (-1x^15)/8y^9
Answers
Answered by
Steve
#30 Your answer is fine, but line 3 has a spurious "-" in -27. Either it was a typo, or you lost it by accident. In any case, 3^-3 = 27, not -27.
Your other syntax is also mangled.
1/((3^-3)(x^-6))
= 1/(1/27 x^-6)
= 27x^6
Your mixing up fractions and negative exponents can cause confusion. I'd have nixed the negative exponents right up front:
1/(3x^2)^-3
= (3x^2)^3
= 27x^6
#42: again correct, but all those factors being cubed confuses me.
(-7x^5/14y^3)^3
= (-x^5/2y^3)^3
= -x^15/8y^9
Your other syntax is also mangled.
1/((3^-3)(x^-6))
= 1/(1/27 x^-6)
= 27x^6
Your mixing up fractions and negative exponents can cause confusion. I'd have nixed the negative exponents right up front:
1/(3x^2)^-3
= (3x^2)^3
= 27x^6
#42: again correct, but all those factors being cubed confuses me.
(-7x^5/14y^3)^3
= (-x^5/2y^3)^3
= -x^15/8y^9
Answered by
Alexis
Thanks for showing how you got rid of the negative exponent on #30. As for #42, that's just how it was on the worksheet. Thanks again.
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