I pick D.
Then you have to add a term to both sides:
1+4+7+10 + + (3k-2)+(3(k+1)-2) = k/2 (3k-1) + (3(k+1)-2)
and then show that
k/2 (3k-1) + (3(k+1)-2) = (k+1)/2 (3(k+1)-1)
watch the parentheses when working online. Things can be misread due to the lack of text formatting.
Can you check my answer?
Which of the following shows the best next step to prove the following by mathematical induction?
1+4+7+10 + + (3n-2)=n/2(3n-1)
1.When n=1, the formula is valid because
(3*1-2)=1/2(3*1-1)
(3-2)=1/2(3-1)
1=1/2(2)
1=1
A. You must show that 1+4+7+10 + + (3(k+1)-2)=k/2(3(k+1-1)
b.You must show that 1+4+7+10 + + (3k-2)+(3(k+1)-2)=k+1/2 (3(k+1)-1)
c. Assuming that 1+4+7+10 + + (3k-1)=k/2(3k-1)
d. Assuming that 1+4+7+10 + + (3(k+1)-1)=k/2(3k-1)
answer:d
1 answer