Can the sides of a triangle have lengths 8, 8, and 16?

1 answer

To determine if the sides of a triangle with lengths 8, 8, and 16 can form a valid triangle, we can apply the triangle inequality theorem. The triangle inequality states that for any triangle with sides of lengths \(a\), \(b\), and \(c\):

  1. \(a + b > c\)
  2. \(a + c > b\)
  3. \(b + c > a\)

In this case, we can assign \(a = 8\), \(b = 8\), and \(c = 16\).

Now, we can check each of the inequalities:

  1. \(a + b > c\): \[ 8 + 8 > 16 \quad \Rightarrow \quad 16 > 16 \quad \text{(not true)} \]

  2. \(a + c > b\): \[ 8 + 16 > 8 \quad \Rightarrow \quad 24 > 8 \quad \text{(true)} \]

  3. \(b + c > a\): \[ 8 + 16 > 8 \quad \Rightarrow \quad 24 > 8 \quad \text{(true)} \]

Since the first inequality \(8 + 8 > 16\) is not true, the lengths 8, 8, and 16 do not satisfy the triangle inequality theorem. Therefore, these sides cannot form a triangle.