Can someone tell me if I am right?
Factor by group
20x^2-12x=15x-9
20x^2+3x+9
(4x+3)(5x-3) answer
7 answers
20x^2-27x-9
meant +9 and then do the rest.
yes, you are right, but you should have maintained your equation.
20x^2+3x+9 = 0
(4x+3)(5x-3) = 0
You could have tested your answer by expanding it to get back the
20x^2+3x+9 = 0
20x^2+3x+9 = 0
(4x+3)(5x-3) = 0
You could have tested your answer by expanding it to get back the
20x^2+3x+9 = 0
oops, just looked at your second line and assumed you would have had that one correct,
Chad is correct above.
Chad is correct above.
So my second line should be:
20x^2-27x+9=0
20x^2-27x+9=0
yes, and it factors to
(5x-3)(4x-3) = 0
test the answer by expanding it
(5x-3)(4x-3) = 0
test the answer by expanding it
Sorry, I put and = when it should have been a +! Is the one below right?
20x^2-12x+15x-9
20x^2-12x+15x-9
= 20x^2+3x-9
= (4x+3)(5x-3)
20x^2-12x+15x-9
20x^2-12x+15x-9
= 20x^2+3x-9
= (4x+3)(5x-3)