L = 2 W + 4
A = W * L
Can someone simply tell me what methods I must use in order to solve this word problem? Please, don't include the answer. I wish to solve this on my own. However, I would truly appreciate it if anyone could evaluate my answer afterwards.
"A rectangle has a width w and its length is 4 units longer than 2 times the width, or 2w + 4. Write a polynomial for the area of the rectangle."
11 answers
L = 2 W + 4
A = W * L
A = W * ( 2 W + 4 )
A = 2 W ^ 2 + 4 W
A = 2 ( W ^ 2 + 2 W )
A = W * L
A = W * ( 2 W + 4 )
A = 2 W ^ 2 + 4 W
A = 2 ( W ^ 2 + 2 W )
Have you provided me with a method or the answer?
Both
Which is which?
Area of rectangle = width * length
So the answer is: A = 2w^2 + 4w?
A = W * L =
W * ( 2 W + 4 ) =
W * 2 W + W * 4 =
2 W ^ 2 + 4 W =
2 ( W ^ 2 + 4 W )
W * ( 2 W + 4 ) =
W * 2 W + W * 4 =
2 W ^ 2 + 4 W =
2 ( W ^ 2 + 4 W )
The answer is 2 ( W ^ 2 + 4 W )? I wouldn't simplify it?
A = 2 w ^ 2 + 4 w
OR
A = 2 ( w ^ 2 + 4 w )
OR
A = 2 w ( w + 4 )
All three is same answer.
OR
A = 2 ( w ^ 2 + 4 w )
OR
A = 2 w ( w + 4 )
All three is same answer.
SORRY:
A = 2 w ^ 2 + 4 w
OR
A = 2 ( w ^ 2 + 2 w )
OR
A = 2 w ( w + 2 )
A = 2 w ^ 2 + 4 w
OR
A = 2 ( w ^ 2 + 2 w )
OR
A = 2 w ( w + 2 )
3 answers