r+s is common.
6 is common to 6 and 12.
Therefore 6(r+s) can be removed from both terms. What is left?
x in the first term and 2y in the second terms. SO
6(r+s)(x-2y)
Can someone show me the steps to do this question:
6x(r+s) - 12y(r+s)
Answer: 6(r+s)(x-2y)
3 answers
Thanks, I understand now, I feel dumb now >_>
Plz show steps to this equation
z^6-64
answer: (z+2)(z-2)(z^4+4z^2+16)
z^6-64
answer: (z+2)(z-2)(z^4+4z^2+16)