Can someone show me the steps for solving this logarithm?

Question

log₄x+log₄12=log<sub448

Thanks!

Answer 1

EDIT:
It's log₄x+log₄12=log₄48

Answer 2

recall log (AB) = log A + log B

so log₄x + log₄12 = log₄48 becomes
log₄(12x) = log₄48
then
12x = 48
x = 4