Can someone show me how to solve these types of problems. i have two that are driving me nuts.as of now.
Problem #1
Simplify:
2radical(12) + 4 radical (27)
Problem #2
evaluate if possible the following
i am going to describe it
in the index it has a 3 then a radical and for the radicand it has negative 27
can't help sorry
I hope I have understood the question.
2radical(l2)=2radical(2x2x3)
2radical(2x2x3)=2radical(2x2)x2radical(3)=2x(2radical(3))
4radical(27)= 2radical(3x2radical(3))
=2radical(3)x4radical(3)
adding the two
2x(2radical(3))+2radical(3)x4radical(3)=
taking 2radical(3) out as a factor
=2radical(3)x(2+4radical(3))
Does this help?
for 3radical(-27)
3radical(27) would be 3 [3x3x3=27)
3radical(-27) would be -3 (-3x-3x-3=-27)
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