dy/dx = 2x
which is the slope of the tangent at any point (x,y) on the parabola
so at (1,2) , the slope of the tangent is 2(1) = 2
since the normal is perpendicular to the tangent, the slope of the normal must be -1/2
equation:
y-2 = (-1/2)(x-1)
you can doctor that up any way you need.
Can someone show how to solve this problem
Find the equation of the line normal to the graph of y = x^2 + 1 that passes through the point (1, 2).
Thanks!
1 answer