log(-9) is not defined
-log9 = log(1/9)
can someone please look over this and tell me if I made a mistake?
log with a base of 3(−9) = 2x
-log with a base of 3(9) = 2x
-2=2x
x=-1
I'm pretty sure I did it right but just incase please look over and let me know if and where I went wrong. Thanks!
3 answers
oh... ok thanks oobleck! Is that the only thing? Also what do you mean that log(-9) is not defined?
logs of negative numbers are not defined.
You want 3^x = -9
But all powers of 3 are positive. You have seen the graph, right?
You want 3^x = -9
But all powers of 3 are positive. You have seen the graph, right?
1 answer