Can someone please help me with this?

Solve x^3-3x^2-10x=0 by factoring.

Take out x.
x(x^2-3x-10)=0

For the polynomial inside the parentheses, you want factors of 10 that will add or subtract to give 3. 10 and 1 gives 11 or 9 so that is no good. But 5 and 2 are ok. 5*2=10 and 5-2=3.
x(x+2)(x-5)=0
I assume you can finish. If not repost and tell us exactly what you don't understand about it.

Would your answers be x=-2 and x=5?

Yes, but there is another answer too. Isn't x=0 (from first x) factored out?

Oh, yes! I was wondering if you do anything with that. Thank you.

Similar Questions
  1. My bad I didn't save this questions link:Solve by factoring. x² - 121 = 0 0 -11 11 11, -11 Solve by factoring. m² + 8m + 7 = 0
    1. answers icon 1 answer
    1. answers icon 1 answer
  2. KUTA SOFTWARE- INFINITE ALGEBRA 1SOLVING QUADRATIC EQUATIONS BY FACTORING SOLVE EACH EQUATION BY FACTORING. 1) (K+ 1) (K - 5) =
    1. answers icon 1 answer
  3. Solve by factoring 2w^2-11=-12I'm having a super hard time with factoring....can someone plz help?
    1. answers icon 2 answers
more similar questions