Mass = 200Lbs * 0.454kg/Lb = 90.8 kg.
Wb = M*g = 90.8 * 9.8 = 889.84 N. = Normal force(Fn).
a = 10Ft/s^2 * 1m/3.3Ft = 3.03 m/s^2.
Fk = u*Fn = 0.25 * 889.84 = 222.5 N. = Force of kinetic friction.
Fap-Fk = M*a.
Fap = Applied or required force.
Fap = ?.
Can someone please help me with this problem?
A 200-1b block rests on a horizontal plane. Find the magnitude of the force P required to give the block an acceleration of 10 ft/s2 to the right. The coefficient of friction between the block and the plane is 0.25.
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