#1 has no volume.
#2.
millimols HF = 354 mL x 0.18 = about 64
mmols F^- = 354 mL x 0.51 = about 180
added NaOH = 35 mL x 0.15 = about 5
.........HF + OH^- ==> F^- + H2O
I........64....0.......180
add............5..............
C.......-5....-5.........+5
E.......59.....0.......185
Substitute into HH equation and solve for pH. NOTE: My "abouts" are estimates. You need to redo each more accurately.
Can someone please help me answer these questions? Is additional information other than what is given needed to solve? Thanks in advance.
1) Calculate the PH of a buffer containing 0.100 M propanoic acid, HC3H5O2 and .100 M NaC3H502 after the following have been added. Ka for acetic acid is 1.3 x 10^-5.
a. 10.0 mL of 2.0 M HCl (assume no volume change occurs when acid is added)
b. 10.0 mL of 2.0 M NaOH (assume no volume change occurs when base is added)
2) A hydrofluoric acid buffer solution has the following concentrations: [HF] = .18M, [F-]= .51M. If 35mL of .15M NaOH is added to 354 mL of the buffer, what is the resultant pH?
1 answer
1 answer