Standard deviation = √npq
1) n = 157
p = .16 (for 16%)
q = 1 - p = 1 - .16 = .84
2) n = 209
p = .12 (for 12%)
q = 1 - p = 1 - .12 = .88
Substitute and calculate.
Can someone please help me answer these questions? I have tried every method I know and the computer still keeps marking the answers as incorrect. Thanks for the help!
1) If the number of 18-34 year olds sampled is equal to the value identified in part "a"(value=157), what is the standard deviation of the percentage that uses an online tax program (to 2 decimals)? [the percentage given of all 18-34 year olds who use online tax program was 16%]
2) If the number of 35-44 year olds sampled is equal to the value identified in part "b" (value=209, what is the standard deviation of the percentage that uses an online tax program(to 2 decimals)? [the percentage given of all 35-44 year olds who use online tax program was 12%)
4 answers
c. How many 65+ year olds must be sampled to find an expected number of at least 25 that use an online tax program to prepare their federal income tax return?.
25/.02 =
1250
1250
No ande publicando cosillas que no son ciertas pendejete ;) pongase a estudiar mijo. Porfa.
atte: babi (aka los chingones hijo de tu chi****** madre)
atte: babi (aka los chingones hijo de tu chi****** madre)