cos x cot^2 x= cos x
cos x cot^2 x - cos x = 0
cos x (cot^2 x - 1) = 0
cosx = 0
cotx = ±1
Now you can just find x, right?
Can someone please explain on how to solve this equation so I can do the others that are similar to this one?
Find the solutions of the equations that are in the interval [0,2pi)
cos x cot^2 x= cos x
Thank you!
1 answer