5.705 is a correct number for the first one; however, you can't have that many significant figures. You are allowed three; therefore, I would round to 5.70 g. Your prof may not round a 5 the same way and could round to 5.71 g.
The second one is correct also; however, you are allowed 3 s.f. and I would give the answer as 25.0 mL.
Same thing for the third one. 25.0 mL.
Can someone please check my work?
Calculate the mass of (NH4)2S2O8 needed to prepare 250mL of a 0.100M solution.
I got 5.705 g.
Calculate the volume of 2.00M KI needed to prepare 250mL of a 0.200M solution.
I got 0.025L or 25mL.
Calculate the volume of 0.100M Na2S2O3 needed to prepare 250mL of a 0.0100M solution.
I got 0.025L or 25mL.
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